Tuesday, July 08, 2014

JEE MAIN RESULT: Normalization Frustrates Students

The Central Board of Secondary Education (CBSE) declared the final ranks of students of JEE(mains) on Tuesday evening.
Nearly 12.7 lakh students had appeared for the exam. CBSE conducts the JEE(mains) for admission to different National Institutes of Technology(NITs), Indian Institutes of  Information Technology(IIITs) and other centrally funded institutes.
The result declared after a long and anxious wait, has however left a large number of students frustrated and angry because of the 'skewed' normalization formula adopted for ranking. Those who scored over 95% in boards were however placed at an advantage.
Last year several petitions challenging the normalization formula used by JEE (main) for ranking students were filed in the Supreme Court and High Courts.
"The problem lies not in the complexity of the normalization formula but in the method of evaluation by the boards. The normalisation formula is set on a basic assumption that boards are following some norms for evaluation. There should ideally be a normal distribution of marks. But in India, a large no of children get very high marks. In such a situation no normalization formula can be effective," says an IIT  professor.
" The normalization formula is skewed. This is a totally absurd way of giving ranks. The two exams, JEE (mains) and the board exams should not have been coupled. The formula is too complex and biased,' said Sanjeev Singhal.
Agrees another student's parent. " In this method of  normalization a student with a high score in JEE(main) and around 90% in board can get a rank much lower than someone who scored less in JEE(main) but had a higher  board percentage."
Shubam(name changed) adds: "Those who got less than half  marks of what I got in the JEE(mains) have got an overall better rank because of normalisation formula. Is this fair and justified?"
Kshitij Garg who started the online petition last year  to reverse the normalization formula told HT :"We started the online petition against normalization formula last year. Since then a lot of students have continued signing it. Currently we have got more than  9000 signatures and we hope that  the new HRD minister Smriti Irani will look into it."
The SK Joshi Committee had consulted several academicians to come up with a viable normalisation formula for ranking. Two formulas were debated on and finally the JEE(interface) group decided to take a middle path by using the average of both the formulas.
Last year it was decided that for admission to NITs to use the JEE (Main) performance and the normalized Board performance in the 60:40 ratio. But after the JEE (Main) results were out, the JEE Interface Group  came up with the complicated  normalization formula which put  many students  at a disadvantage.
Courtesy: HT


  1. Anonymous12:20 PM

    Sir, my options are
    NSIT-ECE , IT .
    Which is best for me??
    I am sc category student.

  2. Anonymous2:00 PM

    Can i gt admisn n aerospace engnrng n iist wd an jeemain air 4044 n obc rank 646???

    1. It takes jee advanced score

    2. Anonymous6:09 PM

      No sir

    3. Anonymous6:11 PM

      Sir i hv 133 n jee advmcd so am eligble... Selectn s based n jeemain ryt?? Cn i gt n

    4. Candidates who are desirous to join B.Tech Programmes in IIST must appear for the Joint Entrance Examination (Main)-2014 conducted by Central Board of Secondary Education (CBSE), New Delhi to qualify themselves to appear for Joint Entrance Examination (Advanced)-2014 conducted by IITs and secure the minimum prescribed category-wise marks in JEE (Advanced)-2014 as given below:-
      (a) General Candidates (GEN): At least 20% marks in aggregate and at least 5% marks in each of the three subjects (Physics Chemistry and Mathematics).
      (b) Other Backward Community – Non Creamy Layer (OBC-NCL) Candidates: At least 18% marks in aggregate and at least 4.5% marks in each of the three subjects (Physics Chemistry and Mathematics).
      (c) Scheduled Caste(SC), Scheduled Tribe(ST) & Persons with Disabilities(PD) Candidates: At least 10% marks in aggregate and at least 2.5% marks in each of the three subjects (Physics Chemistry and Mathematics).
      In JEE-(Advanced), maximum mark for each subject is 120 and the aggregate is 360. Accordingly, the MINIMUM (cut-off) MARKS for each subject and the aggregate, which should be secured for eligibility to apply for B.Tech admission in IIST is tabulated below:
      Subject General OBC-NCL SC/ST/PD
      Physics 6 5 3
      Chemistry 6 5 3
      Mathematics 6 5 3
      Aggregate 72 64 36

  3. Anonymous11:22 AM

    is it better to takeit /ece at nsit or ece at mnnit allahabad ??

    1. Both are pretty much similar but I will go with NIT allahabad

  4. Sourav Chowdhury11:56 AM

    Sir, my AIR is 14620 and i am from general category. Can i get into nit surat/jamshedpur?